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Cost Vs Number of Iterations in Gradient Descent | MATLAB

Prerequisite:



%Code:

clc
clear all
close all
format long
figure;
x=[1,2,3,4,5];
y=[5,7,9,11,13];
m=0;
c=0;
slope=[];
plot(x,y,'bo','linewidth',3);
hold on;
axis([-1 10 0 15]);
cost=[];
intercept=[];
for h=1:10000
predicted=m*x+c;
s=y-predicted;
w=((sum(-2*x.*s))/length(x))*0.08;
m=m-w;
slope=[slope m];
w=((sum(-2*s))/length(x))*0.08;
c=c-w;
intercept=[intercept c];
 e=m*x+c;
 costa=(1/length(x))*sum(s.^2);
 cost=[cost costa];
end
plot(x,m*x+c,'k','linewidth',3);
axis([-1 10 0 15]);
e=[slope' intercept' cost'];
figure;
h=1:10000;
plot(h(1:200),cost(1:200));
xlabel('Iteration');
ylabel('Cost or mean square error');
title('Cost Function');


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