Time Expansion | Problem 2228 | Cody Challenge

How can you slow down any discrete-time signal?

Example

Input original signal x. x = [1 2 3 -1 -2 -5 -4]
We want to slow down n=3 times original signal.

Output signal must be like y. y = [1 0 0 2 0 0 3 0 0 -1 0 0 -2 0 0 -5 0 0 -4]

You can check the question here also:

Click Here

MATLAB Code:

clc

clear all

close all

x=input('Enter the signal'); 

k=input('Enter the required amount of expansion');

Y=[];

j=k-1;

for i=1:length(x)

    Y=[Y x(i)];

    if(i~=length(x))

    for m=1:j

        Y=[Y 0];

    end

    end

end

Explanation:

    

Output:

JAVA CODE:

import java.util.Scanner;

class Wqp

{

public static void main(String args[])

{

Scanner obj=new Scanner(System.in);

System.out.println("Enter the length of the array:");

int l=obj.nextInt();

int a[]=new int[l];

for(int i=0;i<l;i++)

{

System.out.println("Enter the number in array");

a[i]=obj.nextInt();

}

System.out.println("Enter the required amount of expansion");

int p=obj.nextInt();

p=p-1;

for(int i=0;i<l;i++)

{

System.out.print(a[i]+" ");

if(i!=a.length-1)

{

for(int puk=0;puk<p;puk++)

{

System.out.print("0" +" ");

}

}

}

}

}

OUTPUT: